1樓：匿名使用者
private sub form_click()dim s as integer, i as integers = 0
i = 1
dos = s + i
i = i + 1
loop until i = 101
print "s="; s
end sub
執行結果：
s= 5050
2樓：匿名使用者
vb你都會，地球人真是無法阻擋你了，
vb中怎樣使用迴圈結構對a(6)的6個元素賦值1,2,3,4,5,6.並用print語句顯示？
3樓：無敵手了啊
最終使用迴圈結構對六個元素賦值。
4樓：獅子薯片
如果說需要進行相應的應該迴圈顯示的話，我覺得你是可以相關參考相應的說明書。
vb利用迴圈結構程式設計計算表示式1+1/2+1/3+.....+1/n的值
5樓：數學與計算機程式設計
private sub command1_click()static n as long, valsum as doubleselect case command1.captioncase "計算"
valsum = 0
dim i as long
n = inputbox("pleace input integer n:", "inputbox", 10)
command1.caption = "顯示"
for i = 1 to n
valsum = valsum + 1 / inext i
case "顯示"
label1.caption = "n=" + cstr(n)text1.text = valsum
command1.caption = "計算"
end select
end sub
private sub form_load()text1.enabled = falsetext1.text = ""
command1.caption = "計算"
command1.fontbold = truecommand1.fontsize = 22command1.fontname = "宋體"
text1.fontname = "times new roman"
text1.fontbold = truetext1.fontsize = 22
end sub
求解1^3+3^3+5^3+…………（2n-1)^3=????? 用vb迴圈結構程式編寫的**
6樓：網海1書生
那個推薦答案是錯的，他沒有累加，所以得出的結果是最後那個數的計算值private sub form_click()dim i as long, n as long, s as double
n = val(inputbox("請輸入n值"))for i = 1 to n
s = s + (2 * i - 1) ^ 3next
msgbox "計算結果為" & s
end sub
7樓：匿名使用者
option explicit
private function nsancf(n as long) as double
dim djg as double
for n = 1 to 2 * n - 1 step 2djg = n * n * n
next n
nsancf = djg
end function
private sub form_click()dim d as double, n as longn = inputbox("請輸入數字")print str(nsancf(n))
end sub
8樓：
請先學會化簡後在程式設計計算,那樣效率會高很多.